5x+67-5x=-14+x^2

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Solution for 5x+67-5x=-14+x^2 equation:



5x+67-5x=-14+x^2
We move all terms to the left:
5x+67-5x-(-14+x^2)=0
We add all the numbers together, and all the variables
-(-14+x^2)+67=0
We get rid of parentheses
-x^2+14+67=0
We add all the numbers together, and all the variables
-1x^2+81=0
a = -1; b = 0; c = +81;
Δ = b2-4ac
Δ = 02-4·(-1)·81
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18}{2*-1}=\frac{-18}{-2} =+9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18}{2*-1}=\frac{18}{-2} =-9 $

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